x^2+9x=350

Solution for x^2+9x=350 equation:

x^2+9x=350

We move all terms to the left:

x^2+9x-(350)=0

a = 1; b = 9; c = -350;
Δ = b2-4ac
Δ = 92-4·1·(-350)
Δ = 1481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{1481}}{2*1}=\frac{-9-\sqrt{1481}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{1481}}{2*1}=\frac{-9+\sqrt{1481}}{2}
$